Let w = width
Then, 2w + 2(88) = 326
w + 88 = 163
w = 75
Shaundell B.
asked 08/20/19A new Neighborhood Activity Complex, Pagosa Springs. The perimeter of the rectangular playing field is
326. The length of the field is 88. What are the dimensions of the playing field?
Let w = width
Then, 2w + 2(88) = 326
w + 88 = 163
w = 75
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