How do you how do you write nine times a number wise subtract from 85 is seven times the sum of four and y

Answer 1

From what I read:

9(85 - n) = 7(4 + y)

Answer 2

"How do you how do you write nine times a number wise subtract from 85 is seven times the sum of four and y"

I'm interpreting this as....

How do you write nine times a number subtracted from 85, is seven times the sum of four and y?

Let's go through each individual piece of information, starting with "nine times a number". We will let our unknown number be represented by x.

nine times a number = 9x

When something is "subtracted from 85", that means you're starting with 85 and subtracting something.

nine times a number subtracted from 85 = 85 - 9x

For "seven times the sum of four and y", start with the sum of 4 and y. A sum is an expression of addition, so we're adding 4 and y. We'll put that in parentheses and then multiply it with seven.

seven times the sum of four and y = 7 × (4+y)

Back to the original problem, "nine times a number subtracted from 85, is seven times the sum of four and y". Let's fill in everything in order, and replace "is" with an equal sign.

85 - 9x = 7 × (4+y)

So really, we're just translating from words to math symbols. Nine times "a number" could be 9a as well....or 9q, 9σ.....whatever you choose the symbol to be for the unknown number.

I hope this helps!

Answer 3

Remember that:

1. "times" means to multiply;
2. "a subtracted from b" means "b - a" or "b minus a" (i.e. second - first);
3. "sum" means to add the two numbers; and
4. "is" means equals.

So, if n is "a number" then:

"Nine times a number subtracted from 85 is seven times the sum of four and y" becomes...

"9 times n subtracted from 85 is 7 times the sum of 4 and y" becomes...

"9n subtracted from 85 = 7(sum of 4 and y)" becomes...

"85 minus 9n = 7(4+y)" becomes...

85 - 9n = 7(4+y)

So the answer is 85-9n=7(4+y). Tada!