What is a line parallel to 3x-2y=8 that passes through (-1,-7)?

Question

Please help me write an equation. I appreciate it.

Answer 1

The slope of the line, 3x-2y=8 is m=3/2.

So the parallel line will be y=(3/2)x+b.

Since the parallel line is passing (-1, -7), to determine b, put the number x=-1 and y=-7.

-7 = (3/2)(-1) +b

b=-11/2

Therefore, the parallel line to 3x-2y=8 and passing the point (-1, -7) is y=(3/2)x-(11/2).

Answer 2

Greetings! Lets solve this shall we ?

So, we must find an equation of a line parallel to the given line 3x-2y = 8. Then, lets convert the given line into slope-intercept form such that

3x-2y=8

-2y = -3x+8

y = (-3/-2)x + (8/-2)

y = (3/2)x - 4

The new line parallel to this must have the same slope of m = 3/2 while using the point (-1,-7). Next, we use the point-slope formula to find the new line such that

y - y1 = m(x - x1)

y - (-7) = (3/2)(x - (-1))

y + 7 = (3/2)(x + 1)..........Then distribute the 3/2 inside such that

y + 7 = (3/2)x + (3/2).........Then subtract 7 to the other side to get

y = (3/2)x + (3/2) - 7...................(3/2) - 7 = (3/2) - (14/2) = -11/2. Finally,

y = (3/2)x - (11/2)

I hope this helped!