Boyoung C. answered • 08/16/19

AP Calculus, Calculus I, II, III & AP Physics Tutoring

The slope of the line, 3x-2y=8 is m=3/2.

So the parallel line will be y=(3/2)x+b.

Since the parallel line is passing (-1, -7), to determine b, put the number x=-1 and y=-7.

-7 = (3/2)(-1) +b

b=-11/2

Therefore, the parallel line to 3x-2y=8 and passing the point (-1, -7) is y=(3/2)x-(11/2).