Determine the slope of the line that contains the points (-3, -5) and (0, 10)

Answer 1

The slope of a line can be calculated by the equation m=(y₂-y₁)/(x₂-x₁). This means we can assign either point as the first point and the other one is the second point. For this problem, lets say our first point is (-3, -5) and the second point is (0, 10). We can plug these values into the equation.

m=(10-(-5))/(0-(-3))=(10+5)/(0+3) because subtracting a negative is the same as adding a positive.

m=15/3

m=5

Therefore, the slope of the line passing through the points (-3, -5) and (0, 10) is 5.

Answer 2

m = Δy / Δx

m = (-5 - 10) / (-3 - 0)

m = -15 / -3

m = 5

Answer 3

The slope is 5.