Patrick B. answered 08/14/19
Tutor
4.7
(31)
Math and computer tutor/teacher
y = k/x^2
3 = k/1^2 = k/1 = k
y = 3/x^2
Xavier T.
asked 08/14/19Y varies inversely as the square of x and y=3 when x=1
Patrick B. answered 08/14/19
Math and computer tutor/teacher
y = k/x^2
3 = k/1^2 = k/1 = k
y = 3/x^2
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