A rectangular house has a total perimeter of 34 metres, and the width is 5 metres less than the length. What are the dimensions of the house?

Answer 1

Perimeter = 2 * length + 2* width

34 = 2*L + 2*(L-5) <--- width is 5 meters less than the length

34 = 2L + 2L - 10

34 = 4L - 10

44 = 4L

L=11

Length is 11, width is 6