During a week, a city had an day's average temperature of 75 F°. Temperatures for the first three days were 62 F°, 83 F and 76 F°, respectively. What was the average temperature for the other 4 days?

Answer 1

During a week, a city had an day's average temperature of 75 F°. Temperatures for the first three days were 62 F°, 83 F and 76 F°, respectively. What was the average temperature for the other 4 days?

Let the temperatures for the 7 days be A,B,C,D,E,F,G.

The average for the week was (A+B+C+D+E+F+G) / 7 = 75

A+B+C+D+E+F+G = 7*75

A+B+C+D+E+F+G = 525

Temperatures for the first three days are given:

62+83+76+D+E+F+G = 525

D+E+F+G = 525 - 62 - 83 - 76

D + E + F + G = 304

The average for the first 4 days is: (D+E+F+G) / 4

So, divide both sides by 4:

(D+E+F+G) / 4 = 304 / 4

(D+E+F+G) / 4 = 76

The average temperature for the last four days was 76°F.

Answer 2

(7)(75) = 525

62 + 83 + 76 = 221

525 - 221 = 304

304 / 4 = 76