HELP PLEASE! NEED THIS DONE ASAP

Question

Determine the standard form of a quadratic function whose graph has a y-intercept of 8 and a vertex at (-2,-4)

Answer 1

One such equation is x² + 4x + 8

The y intercept is clearly 8.

The x coordinate of the vertex is -4/(2*1) = -2

At x = -4, y = (-2)² + 4(-2) + 8 = -4