Mark M. answered 08/04/19
Retired math prof. Very extensive Precalculus tutoring experience.
f(x) = k - x
g(x) = 9/(x+2)
f(x) = g(x) when k - x = 9 / (x+2)
So, (k-x)(x+2) = 9
-x2 + (k-2)x + (2k-9) = 0
So, x = [-(k-2) ± √((k-2)2 - 4(-1)(2k-9))] / -2
The roots are equal when (k-2)2 + 4(2k-9) = 0
So, k2 + 4k - 32 = 0
(k + 8)(k - 4) = 0
k = 4 or -8
If k = 4, then 4-x = 9/(x+2)
(4-x)(x+2) = 9
-x2+2x+8 = 9
x2-2x+1 = 0 So, (x-1)2 = 0
x = 1
If k = -8, then -8-x = 9/(x+2)
(-8-x)(x+2) = 9
-x2-10x-16 = 9
x2+10x+25 = 0
(x+5)2 = 0
x = -5