Quang T. answered • 08/02/19
GIS Professional with experience in Python and Data Engineering
First list the known factors. x can never be larger than 12 because of the stated limitation of the zoo. This immediately eliminates choice A and D. The reason being is that those constraints do not limit the number of female gazelles. For example, if x= 20, it would be true for the constraints but wrong with the information given.
The next known information is that for a thriving population, males have to be three times the population of females. This eliminates choice C. Since the maximum amount of females possible are 12 then the maximum amount of males that can be placed is 36. Choice C states that the zoo can only have more than 36 male gazette. This is not true with the information given.
This leaves only choice B as the correct answer.
Quang T.
The question does not say greater than 3 times the females. It says for a thriving population, males need to be 3 times the amount of female. If we're being liberal with the wording, a thriving population needs at least 3 times the amount of female. Regardless of which two interpretation you agree with, when there are 12 female gazelles there will be an instance where there are 36 male gazelles. Choice C says there can never be 36 male gazelles which is not true. Thrive = x + y = x +3 x. If x is 12, y equals 36 which choice C says is impossible; not true. The constraints of the two variables have no direct relation to each other. They have a relationship with the formula/equation.08/02/19
Keith B.
08/02/19