x + y = 20
x2 + y2 = 232
x2 + (20-x)2 = 232
x2 + 400 - 40x + x2 = 232
2x2 - 40x + 168 = 0
x2 - 20x + 84 = 0
(x - 6)(x - 14) = 0
The numbers are 6 and 14. .
Dens D.
asked 07/31/19Te sum of two numbers is 20 and the sum of thier squares is 232. Find the numbers.
x + y = 20
x2 + y2 = 232
x2 + (20-x)2 = 232
x2 + 400 - 40x + x2 = 232
2x2 - 40x + 168 = 0
x2 - 20x + 84 = 0
(x - 6)(x - 14) = 0
The numbers are 6 and 14. .
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