Amirou S.

asked • 07/29/19

Algebraic Math Question

for the equation kx^2 - (1+k)x + (3k+2) = 0, how do i find the value of k ?

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Whiz S. answered • 07/29/19

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kx^2 - (1+k)x + (3k+2) = 0


kx^2 - x - kx + 3k + 2 = 0

kx^2 - kx + 3k - x + 2 = 0

kx^2 - kx + 3k = x -2

Factor out the k:

k(x^2 - x + 3) = x - 2

Divide both sides by (x^2 - x + 3)

k = (x - 2)/(x^2 - x + 3)


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Amirou S.

I might've not been specific enough, so that's my bad on my part. But I'm using the HL Core Mathmatics Haese Pearsons text book, and I'm practicing on the Quadratic chapter under the section of "The Sum And product of The Roots". In this particular question it ask as I quote "The equation kx^2 - (1+k)x + (3k+2) = 0 is such that the sum of its root is twice their product. Find k and the two roots. " So I think that somehow the variable 'k' has an actual numerical value but I don't understand how to solve that?
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07/30/19

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