Arthur D. answered 07/26/19
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
distance=rate*time
d=r*t
d(1)=80*t
d(2)=100*(5-t)
80t+100(5-t)=440
80t+500-100t=440
500-20t=440
500-440=20t
60=20t
t=3 hours
d(1)=80*3=240 km
d(2)=100(5-3)
d(2)=100(2)
d(2)=200 km
240+200=440