Let a = hours for first mechanic
b = hours for the second mechanic
Then
a + b = 35
and 105a + 110b = 3750
Solving the two equations simultaneously, we find that a = 20 & b = 15
First Mechanic worked 20 hours
Second Mechanic worked 15 hours
Jonathan V.
asked 07/25/19Two mechanics worked on a car. The first mechanic charged $105 per hour, and the second mechanic charged $110 per hour. The mechanics worked for a combined total of 35 hours, and together they charged a total of $3750 . How long did each mechanic work?
Let a = hours for first mechanic
b = hours for the second mechanic
Then
a + b = 35
and 105a + 110b = 3750
Solving the two equations simultaneously, we find that a = 20 & b = 15
First Mechanic worked 20 hours
Second Mechanic worked 15 hours
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