A solution of 10% sulfuric acid and one of 25% sulfuric acid are to be used to make 500 ml of 20% sulfuric acid. how many ml of each solution needs to be used in the mixture?

Question

A solution of 10% sulfuric acid and one of 25% sulfuric acid are to be used to make 500 ml of 20% sulfuric acid. How many ml of each solution needs to be used in the mixture? (Answer to the nearest ml)

Answer 1

Let x = number of ml of 10% solution

Then, 500 - x = number of ml of 25% solution

So, 0.10x + 0.25(500 - x) = 0.20(500)

0.10x + 125 - 0.25x = 100

-0.15x = -25

x = 166 2/3 ml

Use 166 2/3 ml of 10% solution with 333 1/3 ml of 25% solution.