Mark M. answered 07/21/19
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Area = ∫(from -3 to 3) [81 - x4]dx
= 2∫(from 0 to 3)[81 - x4]dx = 2(81x - (1/5)x5)(from 0 to 3)
= 2(243 - 243/5) = 388.8
Mark M. answered 07/21/19
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Area = ∫(from -3 to 3) [81 - x4]dx
= 2∫(from 0 to 3)[81 - x4]dx = 2(81x - (1/5)x5)(from 0 to 3)
= 2(243 - 243/5) = 388.8
Patrick B. answered 07/21/19
Math and computer tutor/teacher
The integral is 81x - (1/5)x^5
x-->3 : 81*3 - (1/5)(3^5) = 243 - 243/5 = 162
x-->-3: 81*-3 - (1/5)(-3)^5 = -243 - (-243/5) = 243/5 - 243 = -162
The area is 162- -162 = 324
Again, as a sanity check, there are TWO right triangles with height 80 and base 3.
That is 2 * (1/2) * 80 * 3 = 240
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