
Bobosharif S. answered 07/19/19
PhD in Math, MS's in Calulus
[g(x+h)-g(x)]/h
=[5-(x+h)2-5-x2]/h
=[5-(x2+2xh+h2)-5-x2]/h= -(2xh+h2)/h=-2x-h
Bobosharif S. answered 07/19/19
PhD in Math, MS's in Calulus
[g(x+h)-g(x)]/h
=[5-(x+h)2-5-x2]/h
=[5-(x2+2xh+h2)-5-x2]/h= -(2xh+h2)/h=-2x-h
Bobosharif S. answered 07/19/19
PhD in Math, MS's in Calulus
[g(x+h)-g(x)]/h
=[5-(x+h)2-5-x2]/h
=[5-(x2+2xh+h2)-5-x2]/h= -(2xh+h2)/h=-2x-h
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