a + b = 195
10a + 15b = 2450
a = 195 - b
10(195 - b) + 15b = 2450
1950b - 10b + 15b = 2450
5b = 500
b = $100
a = 195 - 100
a = $95
Alyssa W.
asked 07/11/19Two mechanics worked on a car. The first mechanic worked for 10 hours. And the second mechanic worked for 15 hours. Together they charged a total of $2450. What was the rate charged per hour by each mechanic if the sum of the two rates was $195 per hour?
a + b = 195
10a + 15b = 2450
a = 195 - b
10(195 - b) + 15b = 2450
1950b - 10b + 15b = 2450
5b = 500
b = $100
a = 195 - 100
a = $95
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