what is the answer to x-5/2x^2 divided by x-5/6x

Question

Then find the excluded values of x. If anyone can help me get the answer ill be forever grateful.

Answer 1

clearly, x≠0, since that would make each fraction undefined.

As you know, when dividing by a fraction, invert it and multiply. That gives you

(x-5)/(2x^2) * (6x)/(x-5)

The 2x and (x-5) cancel, leaving just 3/x, providing that x≠0