
Patrick B. answered 07/11/19
Math and computer tutor/teacher
distance = rate * time
425 = (r+15)* t = rt + 15t
350 = (r-15)*t = rt - 15t
775 = 2rt
387.5 = rt
Substitutes:
425 = 387.5 + 15t
350 = 387.5 - 15t
Solves:
37.5 = 15t
=37.5 = -15t
SO t = 2.5
Substitutes again:
425 = (r + 15)* 2.5
4250 = 25(r+15) <--- multiplies by 10
170 = r + 15
r = 155
The speed of the plane is 155 mph
With the wind, 2.5 ( 155+15) = 2.5 * 170 = 425
Against the wind 2.5( 155-15) = 2.5*140 = 350
The speed of the plane is 155 mph
Amanda B.
thank you :)07/11/19