Mike correctly found the slope and y-intercept of the line passing through the points (–5, –2) and (3, 14) What is the equation of the line in slope-intercept form?

Question

Mike correctly found the slope and y-intercept of the line passing through the points (–5, –2) and (3, 14) What is the equation of the line in slope-intercept form?

Answer 1

In this problem two points were giving ( -5, -2) and ( 3, 14). = ( X1, Y1) , (X2, Y2).

Y2 -Y1

1. Let find the slope of the line m = -----------------=. 14- (-2). /. 3- (-5). = 14+2/3+5 = 16/8 =2

X2-X1

2. m=2. The equation of the line in slope -intercept form is y = mx+b

3. b=? you need to find b, knowing that m=2, y= -2 and x= -5, let substitute in y = mx+b

4 -2 = 2(-5) +b

-2 = -10 +b Adding +10 in both sides we get 8=b

Therefore the answer is y= 2x +8

Note: To check your answer ,you can graph ( using ti-84) the equation y= 2 x+8, press 2nd graph and notice a table that has the points ( -5,-2) and (3,14).

looks like this:

x. y

-5. -2

-4. 0

-3. 2

-2. 4

-1. 6

0. 8

1. 10

2 12

3. 14

If you should need additional help , please contact me and I can further assist you.