
Roxanne G. answered 07/10/19
Experienced Tutor: Algebra, Geometry, Essay Writing
Factors of 56:
8 x 7 8 + 7 =15
2 x 28
4 x 14
etc.
The two numbers are 8 & 7
Houda A.
asked 07/10/19Roxanne G. answered 07/10/19
Experienced Tutor: Algebra, Geometry, Essay Writing
Factors of 56:
8 x 7 8 + 7 =15
2 x 28
4 x 14
etc.
The two numbers are 8 & 7
Michael D. answered 07/10/19
Versatile STEM tutor eager to teach
You can also solve the problem without looking at the factors of 56...
Equation 1 : A*B = 56
Equation 2 : A + B = 15
Solve for A or B in one of the equations and plug the solution into the other equation... I'll solve for A using the 2nd equation
A + B = 15
subtract B from both sides
A = 15 - B
Plug solution into the 1st equation
A*B = 56
(15 - B)*B = 56
15B - B2 = 56
subtract (15B - B2) from both sides and reorganize.... (I did it that way so the B2 coefficient is positive)
B2 -15B + 56 = 0
solve via quadratic equation
[ -b ± √(b2 - 4ac) ] / 2a
[ 15 ± √(1) ] / 2
Roots are : 7 & 8
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You could also of done it the other way...
I'll solve for A using the 1st equation :
A*B = 56
Divide by B
A = 56/B
Plug into the 1st equation :
A + B = 15
56/B + B = 15
Multiply both sides by B
56 + B2 = 15B
reorganize...
B2 -15B + 56 = 0
and you have the same thing we had doing it the other way...
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Check your work!!
Answers are 7 & 8
Equation 1 : A*B = 56
7 * 8 = 56 correct
Equation 2 : A + B = 15
7 + 8 = 15 correct
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