Brianna C. answered 07/11/19
Medical Resident: 99th %ile: MCAT, Science, Math, Spanish
To solve this problem, you have to solve for 2 variables (number of 2 point questions and number of 4 point questions). So, the best way to approach it is a system of equations.
Lets call X 2 point questions and Y 4 point questions.
There are 34 questions so X+Y=34
There are 80 total points so 2X + 4Y= 80 (basically, 2 times the number of 2 point questions plus 4 times the number of 4 point questions makes up the total number of points.
So, with those two equations, let's solve.
X+Y= 34
2X+4Y=80
This equation looks easiest to do by elimination, so lets multiply the entire first equation by 2 so the Xs cancel
2(X+Y=34) comes to
2X + 2Y= 68
Now, subtract this from the other equation to solve
2X+4y=80 - (2X+2Y= 68)
2y= 12
y=6
There are 6 4 point questions.
Now, lets solve for 2 point questions by plugging into the original equation, choosing the easier one.
X + 6=34
X= 28, there are 28 2 point questions.
You should then quickly make sure your numbers work in the original equation
2X+4y=80
2(28) + 4(6)=80
56 + 24= 80
80=80
It checks out :) .
That's it!