I need help in writing an algebraic equation

Question

There are 90 hockey sticks arranged in 4 groups. The second group has 9 more than the first group. The third group has half as many hockey sticks as the second group. The fourth group has 5 fewer hockey sticks than the sum of the hockey sticks in the second and third groups. The number of sticks in the fourth group is also twice as many as the number of hockey sticks in the first group. How many hockey sticks are in each group?

Answer 1

Number of hockey sticks in first group = x

number of hockey sticks in second group = (x+9)

number of hockey sticks in third group =( x+9)/ 2

number of hockey sticks in fourth group =(x+9)+(x+9)/2 - 5

=(2x+18+x+9-10)/2

=(3x+17)/2

The number of sticks in the fourth group is also twice as many as the number of hockey sticks in the first group

3x+17 / 2 = 2x

3x+17=4x

x=17

Number of hockey sticks in first group = x= 17

number of hockey sticks in second group = (x+9)= 17+9=26

number of hockey sticks in third group =( x+9)/ 2=26/2 =13

number of hockey sticks in fourth group =(3x+17)/2 =(3(17)+17)/2 = (51+17)/2 =34

Answer 2

X,Y,Z,W are the four groups

Y = X+9

Z = Y/2 = (X+9)/2

W=(Y+Z)-5

W = 2X

90 = X + Y + Z + W

= X + X+9 + (X+9)/2 + 2x

= (9/2)X = 27/2

180 = 9x + 27

153 = 9x

x = 17

Group #1 has 17

Group #2 has 26

Group #3 has 13

Group #4 has 34