Laurie C. answered 07/02/19
Harvard Precalculus Algebra Geometry Trig SAT/ACT College Essays
For this type of problem, you will need to set up a system of equations. This is because you have two variables, the number of chairs and the number of tables. You can assign x and y for your variables, but it might be more helpful to use c for chairs and t for tables.
9 c + 7 t = $77
3 c + 5 t = $49
to solve the system you can use elimination or substitution. Either will work, but I elimination appears easier here.
Multiply the second equation all the way through by -3 so that you have 9c on top and -9c on bottom.
9c + 7t = 77
-9c -15t = -147 Now add the equations
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0 -8t = -70
t= 70/8 solve for t
t = $8.75 each table costs $8.75
Substitue this t value into one of the original equations to solve for c.
9c + 7(8.75) =77
9c = 15.75
c= $1.75 each chair costs $1.75