what’s the 8th term of f(n)=f(n-1)+7

Question

The first terms are 2, 3, 4.

Answer 1

Does not make sense...

If the first term is 2, then f(1) = 2.

So then f(2) = f(1)+7 = 2+7 = 9.

f(3) = f(2)+7 = 9+7=16

f(4) = f(3)+7 = 16+7 = 23

f(5) = f(4) +7 = 23+7 = 30

f(6) = f(5)+7 = 30+7 = 37

f(7) = f(6) +7 = 37 + 7 = 44

f(8) = f(7) +7 = 44 +7 = 51

If the first term is 3, then the sequence becomes 3,10,17,24,31,38, 45, 52.

If the first term is 4, then the sequence becomes 4,11,18,25,32,39,46,53