The length of a rectangle is 2 m longer than its width. If the perimeter of the rectangle is 60 m, find its length and width.

Answer 1

First, we write the information in algebra:

The length of a rectangle is 2m longer than its width.

L = 2 + W

The perimeter of the rectangle is 60m.

P = 60

We also know the formula for perimeter is P=2L+2W, so 60 = 2L+2W

We can substitute from L=2+W, so:

60=2(2+W)+2W

Then solve:

60=2(2+W)+2W

60=4+2W+2W

60=4+4W

56=4W

14=W

Since we know L=2+W, we can substitute 14 for W.

L=2+14

L=16

Our answer is:

L=16 m

W=14 m

Answer 2

60=2w+2(w+2)

=4w+4

56=4w

14=w

16=L