I think the equation you are looking for is f(t) = f(0)*exp(-t ln 2/t1/2)
where exp is the exponential function ex and t1/2 is the half-life in days.
This should allow you to answer the questions.
Chen C.
asked 06/22/19Physicians use gallium citrate-67 to detect certain types of cancer, including lymphoma. Gallium citrate-67 has an effective half-life of 3.24 days—some is lost to radioactive decay, and some is removed through the digestive and urinary tracts. A patient who is breast-feeding is injected with the radioactive element.
Let
f(t)
be the percentage of the gallium citrate-67 that remains in the patient’s body at t days since she was injected. Find an equation of f.
f(t)=
A scan of the gallium citrate-67 is performed 2 days after the injection. What percentage of the element remains?
____%. Round to 2 decimal places.
The patient can resume breast-feeding when only 0.39% of the gallium citrate-67 remains. When can she resume breast-feeding?
_____days Round to 1 decimal place.
I think the equation you are looking for is f(t) = f(0)*exp(-t ln 2/t1/2)
where exp is the exponential function ex and t1/2 is the half-life in days.
This should allow you to answer the questions.
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