The integral is 18t-70e-t-24t2.
Evaluate it between 0 and 40 and divide the result by 40.
Chen C.
asked • 06/22/19integral problem
If a cup of coffee has temperature 88°C in a room where the ambient air temperature is 18°C, then, according to Newton's Law of Cooling, the temperature of the coffee after t minutes is T(t)=18+70e−t/48. What is the average temperature of the coffee during the first 40 minutes?
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