Jon P. answered 01/09/15
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is this 1/x2 - 3/x = 8?
If so...
Multiply both sides by x2. (This is only OK if x is not 0, but we know that because if it were then the whole equation would be invalid, because there are terms that have x in the denominator, which is not allowed if x is 0.)
1 - 3x = 8x2
0 = 8x2 + 3x - 1
Use the quadratic formula:
x = (-b ± √(b2-4ac)) / 2a
x = (-3 ± √(9 -4*8*(-1))) / 16
x = (-3 ± √41) / 16
So the solutions are:
(-3 + √41) / 16
(-3 - √41) / 16