How do I find the height when point A is 125m away from tower PQ and the angle of elevation of the top (P) of the tower from A is 71°?

Answer 1

Point A is 125 m away from Tower PQ. The angle of elevation from point A to tower PQ is 71 degrees. We need to find the height of the tower.

sine = opp/hypotenuse

cosine = adjacent/hypotenuse

tangent = opposite/adjacent

To find the height of the tower, multiply tan(71)* 125. You get 363.026 m as the height of the tower.

Height of Tower PQ = 363.026 m

Answer 2

The best way to approach this problem is to draw it out.

In this case, it would be a triangle.

The base would be 125 m, the height PQ would be unknown, x.

Angle PAQ would be 71 degrees.

Using trigonometry:

tan 71° = x/125

x = 125 tan 71° = 363 m

Tower PQ is 363 m tall.