Stochiometry question.

Question

Use the below equation, how many grams of lithium nitrate is required to produce 250g of lithium sulfate?

Pb(SO4)2 + 4LiNO3 = Pb(NO3)4 + 2Li2SO4

Answer 1

Pb(SO₄)₂ + 4LiNO₃ = Pb(NO₃)₄ + 2Li₂SO₄

moles Li₂SO₄ desired = 250 g x 1 mol/110 g = 2.27 moles

moles LiNO₃ required = 2.27 moles Li₂SO₄ x 4 moles LiNO₃/2moles Li₂SO₄ = 4.54 moles LiNO₃ needed

mass LiNO₃ needed = 4.54 moles x 1 mole/68.9 g = 313 g required.