These types of problems are derived from an iterative addition of interest bearing money. In the case, the $150 is added at the beginning of each month and then at the end of the month, interest is earned. This money is then the basis for the next month. The monthly interest rate is .09/12 = .0075.
Start of Month End of Month
Month 1 150 150(1.0075)
Month 2 150(1.0075) + 150 (150(1.0075)+150)(1.0075) = 150(1.0075)2 + 150(1.0075)
if you follow this trend, at the end of the 4 year/48 month period, the sum of money will be
Sum = 150(1.0075)48 + 150(1.0075)47 + ........... + 150(1.0075)2 + 150(1.0075)
In order to sum the series, multiply it by (1.0075) to obtain
(1.0075)Sum = 150(1.0075)49 + 150(1.0075)48 + ........ + 150(1.0075)3 + 150(1.0075)2
Then, (1.0075)Sum -Sum = 150(1.0075)49 - 150(1.0075) Then the sum is
Sum = { 150(1.0075)49 - 150(1.0075) }/(1.0075 - 1) = $8,692.82 Now for the next 20 years at
the same interest rate with nothing more deposited, we have
Total = 8,692.82(1.0075)240 = $52,236.47 There are standard formulas for this but I
thought I would show where it comes from!