Jesse E. answered 06/12/19
Experienced tutor for TEAS, chemistry, and biology
x-4y / 5x+y = 3/5 Cross-multiply
5(x-4y) = 3(5x+y) Distribute
5x-20y = 15x+3y Combine like terms on both side.
-10x = 23y Solve for x
x = -23y/10
To fine the value of x/3y, substitute in the x value:
x/3y
(-23y/10)/3y To cancel out 3y, multiple the denominator and the numerator by 1/3y
-23y/30y The y's will cancel.
-23/30
The value of x/3y is -23/30.