The ages of 3 brothers are consecutive integers that gives a sum of 84 how old are the brothers?

Answer 1

In this question, the ages were consecutive integers. Therefore, X, X+1, X+2 as shown above. You will sometimes see, "Consecutive odd integers" or "Consecutive even integers" Then the math would show:

X + (X+2) + (X+4) = whatever number. Solve as before for X. Easy!!

Answer 2

You have three brothers whose ages are consecutive integers which means they are something like 1, 2, and 3 or maybe 20, 21, and 22. When you add their three ages together, you get 84, so how old are each of the brothers?

Let x = age of the youngest brother. Consecutive integer ages mean each brother is one year older than the last. That means:

x + 1 = age of middle brother, and

x + 2 = age of oldest brother.

Thus: x + (x + 1) + (x + 2) = 84. You can combine like terms to get 3x + 3 = 84. Subtracting 3 from both sides means 3x = 81. Dividing by 3 on both sides gives you x = 27. Thus the age of the youngest brother is 27, the x + 1 = 28 is the age of the second brother, and x + 2 = 29 is the age of the oldest brother.

Let's check our work: Does 27 + 28 + 29 = 84? 👍

Answer 3

Hi Brittany!

If we let x represent the age of the youngest brother, then the other two brothers' ages are x+1 and x+2. This is because their ages are consecutive. The middle brother is one year older than the youngest brother (thus x+1), and the oldest brother is two years older than the youngest brother (thus x+2).

Next, the question says that the sum of the ages is 84. Remember that sum means addition. Therefore:

(x) + (x+1) + (x+2) = 84

At this point, we can simplify and solve!

3x + 3 = 84

3x = 81

x = 27

So the youngest brother is 27, the middle brother is 28, and the oldest brother is 29!