Eugene E. answered 08/10/23
Math/Physics Tutor for High School and University Students
Each basic open set (-∞, a] intersects both (0,1) and its complement. Therefore, every point on the real line is a boundary point of (0,1), and ∂(0,1) = R.
Luis P.
asked 06/06/19Consider the topology on $\mathbb{R}$, $\tau(\mathcal{E})$ where $\mathcal{E} = \{(-\infty, a] : a \in \mathbb{R}\}$. What is the boundary of $(0,1)$?
I know that $bd(0,1) = cl(0,1) \setminus int(0,1)$, but am not sure how to determine $cl(0,1)$ and $int(0,1)$.
Eugene E. answered 08/10/23
Math/Physics Tutor for High School and University Students
Each basic open set (-∞, a] intersects both (0,1) and its complement. Therefore, every point on the real line is a boundary point of (0,1), and ∂(0,1) = R.
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