The sum of three consecutive integers is 267. What is the largest integer?

Answer 1

Its 90

Let the starting integer = x

The next consecutive integer = x +1

The final of the three consecutive integers = x + 2

x + (x + 1) + (x +2) = 267

x + x +1 + x + 2 = 267

Combine like terms

3x + 3 = 267

Subtract 3 from both sides of the equation

3x = 264

Divide both sides of the equation by 3

x = 264/3

x = 88

88 is the smallest we want the largest so we can substitute this value in x + 2 to get the largest

88 + 2 = 90

90 is the largest of the three consecutive integers

Checking

88 + 89 + 90 = 267

267 = 267

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Answer 2

If your first integer is x, then the next two are (x + 1) and (x + 2).

The sum of these three numbers is 267, so: x + (x + 1) + (x + 2) = 267

Combining like terms you get 3x + 3 = 267

Subtract 3 from both sides to get 3x = 264

Divide both sides by 3 and you get x = 88, which is your first integer.

Your second integer is (x + 1), so 88 + 1 = 89, your second integer. And 90 is your third.

Check and dd 88, 89 and 90 and you get 267

Your integers are 88, 89 and 90