what is the equation in standard form of the line that passes through (-3,-5) and has a slope of 2

Question

I need to find out what equation in standard form passes through the line and has a slope of two 

Answer 1

First find the equation in slope-intercept form:

 

y = mx + b, where m is the slope and b is the y intercept.

 

So fill in the information you have, which is that (-3, -5) is on the line, and the slope is 2:

 

-5 = 2(-3) + b

-5 = -6 + b

1 = b

 

So the slope-intercept form is y = 2x + 1

 

To convert to standard form, put all the variables on the left and keep the constant on the right:

 

y = 2x + 1

 

Subtract 2x from both sides:

-2x + y = 1

 

That's sufficient, but to make it look a little better, multiply both sides by -1:

2x - y = -1

 

 

Answer 2

Standard form of a linear equation is Ax + By = C

You can use the point-slope formula first and solve for the other information

point-slope formula is y-y₁ = m(x - x₁) ; where m is slope

You're given slope m = 2

You're given point (-3, -5)

So equation is:

y - (-5) = 2(x - (-3))

y + 5 = 2(x + 3)

y + 5 = 2x + 6

Simplifying to standard form: (subtracting 5 from both sides and subtracting 2x from both sides at the same time)

-2x + y = 1; or by multiplying both sides by -1 as in Jon's solution 2x - y = -1