Math percentage

Question

an actor invests some money at 7% and $44000 more than three times the amount at 12%. the total annual interest earned from the investment is $63330. how much did he invest at each amount?

Please help

Answer 1

The amount at 7% is A. The amount at 12% is B = 3A+44000.

Look at the problem statement. Do you see where these came from?

The total interest earned is (0.07)(A) + (0.12}(3A+44000) = 63330.

Solve the equation for A:

0.07A +0.36A+5280 = 63330

0.43A = 63330-5280

0.43A = 58050

A = 135,000

B = 3A+44000.= (3) (135000)+44000

B = 449,000