Please help last day!!

Question

Solve each equation for 0≤θ<2π

1)4sin²θ+4=5

2)tanθsinθ-4tanθ=-3tanθ

3)cos²θ=2+2sinθ

Show your work!

Answer 1

1) 4sin²Θ+4=5

4sin²Θ-1=0

The difference of two perfect squares

(2sinΘ+1)(2sinΘ-1)=0

solving each factor for 0, you get sinΘ= +1/2 and - 1/2

On the interval of 0 to 2∏ this happens four times (two each) 30, 150, 210 and 330 degrees, or ∏/6, 5∏/6, 7∏/6 and 11∏/6 radians.

will try to answer the rest later.