
Patrick B. answered 05/29/19
Math and computer tutor/teacher
first circle: (x-k)^2 + (y-C)^2 = r^2
second circle: (x-a)^2 + (y-b)^2 = R^2
solves 2nd circle for x:
x = sqrt( R^2 - (y-b)^2) + a
substitutes into first circle equation:
[sqrt( R^2 - (y-b)^2) + (a-k)]^2 + (y-C)^2 = r^2
FOILS left side
(R^2 - (y-b)^2) + 2 * (a-k)*sqrt(R^2 - (y-b)^2 + (y-b)^4) + (y-C)^2 = r^2
(R^2 - (y-b)^2) + 2 * (a-k)*sqrt(R^2 - (y-b)^2 + (y-b)^4) + (y-C)^2 - r^2 = 0
You can now do newton's method on this equation