Solve using appropiate method z+y=10, x-y=8

Answer 1

We need a third equation, as there are 3 unknowns.

z = 10 - y

x=y+8

so the solution set is (y+8, y, and 10 - y)

So now, solutions can be generated for selected values of free variable y

For example, if y=0, then the solution is (8,0,10)

if y=1, the the solution is (9,1,9)

etc