if -2<y square+ny+1<0 is satisfied by y= -2 ,then what is one possible value of n?

Question

sir can u help if related problems come then how to understand

Answer 1

-2 <y²+ ny + 1 <0

 

if this is true when y = -2  we can substitute and solve for n

 

-2< y² +ny + 1 <0

 

-2 < (-2)² -2n +1

 

-2 < 5 -2n

 

-7 < -2n

 

n<3.5

 

now lets solve the other side

 

(-2)² -2n + 1 <0

 

5 -2n <0

 

-2n <-5

 

n>2.5

 

so a possible value that satisfies both parts of the inequality would be any number between 2.5 and 3.5

 

so let n = 3  as one possible solution