Larry C. answered • 05/24/19
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(n2-1)/(n+1) * (2/(n-2)) = ((n+1)(n-1))/(n+1) * (2/(n-2)) = (n-1) * ((2/(n-2) = 2(n-1)/(n-2)
Sabi G.
asked • 05/23/19Maths - Algebraic Fraction GCSE
How would you solve this : n2-1/n+1 x 2/n-2
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