
Michael D. answered 05/23/19
Versatile STEM tutor eager to teach
First let's develop equations from the problem given
***NOTE, since MPH is in Miles and Hours, and the given information is in Miles and Hours, no Unit conversion is needed. Thus, I won't put in the units below***
let the following be givens :
t75 = time at 75 mph in hours
t90 = time at 90 mph in hours
Equation 1 : ( 75 * t75 ) + ( 90 * t90 ) = 800
Equation 2 : t75 + t90 = 10
Use Equation to solve for t75
t75 + t90 = 10
subtract t90 from both sides
t75 = 10 - t90
Plug that value of t75 into Equation 1 to solve for t90
( 75 * (10 - t90) ) + ( 90 * t90 ) = 800
750 - 75*t90 + 90*t90 = 800
combine like terms
750 + 15*t90 = 800
subtract 750 from both sides
15*t90 = 50
divide both sides by 15
t90 = 3.3333 hours (10/3 to be exact)
plug that into Equation 2 to solve for t75
t75 + t90 = 10
t75 + 3.333 = 10
subtract 3.333 from both sides
t75 = 6.666 hours (20/3 to be exact)
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Always check your work!
( 75 * t75 ) + ( 90 * t90 ) = 800
( 75 * (20/3) ) + ( 90 * (10/3) ) = 800
CORRECT!!
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How many miles doing 75 & 90 mph?
distance75 = 75 * (20/3) = 500 miles
distance90 = 90 * (10/3) = 300 miles
I hope this helps you.