
David W. answered 05/23/19
Tutor
4.7
(90)
Experienced Prof
a0=-13
a1=13
ak-2 +ak-1 [for k>1]
a0 = -13
a1 = 13
a2 = a0 + a1 = -13 + 13 = 0 [note: k=2]
a3 = a1 + a2 = 13 + 0 = 13 [k=3]
a4 = a3 + a2 = 0 + 13 = 13 [k=4]
Note that some sequences begin with a0 and some with a1. These are "the first five terms."