The sum of three numbers is three times the first,and the third is four more than one third the first, the sum of these numbers is 43. Find the three numbers

Answer 1

Let the numbers be X, Y, Z

The sum of three numbers is three times the first

X + Y + Z = 3X ------- (i) =====>> Y + Z = 2X ------------- (ii)

and the third is four more than one third the first

Z = 4 + X/3 ------------(iii)

The sum of these numbers is 43.

X + Y + Z = 43 --------(iv)

Equating the RHS of i and iv

3X = 43 ======>>> X =43/3

From iii

Z = 4 + 43/9 =79/9

From ii

Y + Z =2X

Y = 2X - Z = 2(43/3) - 79/9 = 86/3 - 79/9 = 179/9

The numbers are 43/3, 179/9 and 79/9