Cone A has 3 times the radius and 3 times the height of Cone B. The volume of Cone B is 25pi cubic feet. What is the volume of Cone A?

Answer 1

cone "a" radius=3r

height=3h

bh/3=(r*3)^2pi*(h*3)/3=?

cone "b"=r^2*pi*h/3=25

r^2*pi*h=75

r^2*h=235.62

Need more values.

Answer 2

The volume of a cone is πr²h/3. So for cone B you have πr²h/3=25π. Divide both sides by π and multiply both by 3 giving r²h=75.

Now let X be the volume of Cone B, which by the problem has dimensions 3h and 3r, the formula gives us x=(3r)²(3h)/3 or x=9r²h We can substitute 75 for r²h, since we determined from cone B that r²h=75.

So that gives us x=9(75) or x=675