Alright, Laura, I hope I can still help!
Let's let w = our width of both areas.
Then, the length of the first is 2w + 2, 2 m more than twice the width.
The length of the second is w - 3, 3 m less than the width.
The fencing goes around the outside, so we need to find the perimeter of our areas.
P = 2l + 2w, right? We have to find the perimeter of both!
2(2w + 2) + 2w + 2(w - 3) + 2w = 4w + 4 + 2w + 2w - 6 + 2w = 10w -2.
So, we have P = 10w - 2.
Hope this helps!