
Al P. answered 05/20/19
Online Mathematics tutor
For an infinite geometric progression that converges (which this one does), the sum is
S = a1 / (1-r)
where
a1 is the first term of the geometric progression
r is the common ratio
Notice that we need to pull the leading -2 out in front, as it otherwise breaks the progression.
That leaves a1 = 1/2 and r = -1/4:
S = -2 + (1/2) (1 / (1-(-1/4)))
= -(10/5) + (2/5)
= -8/5

Al P.
I was mistaken, -2 does not break the progression, as -2 * (-1/4) = 1/2, so its all good: S = -2 / (1-(-1/4)) = -8/5 straight-away. My answer was ok, just the process was unnecessarily complicated, sorry about that.05/20/19